求助c++題目，拜托大神
#include<stdlib.h>
char* month_str[]={"壹月","二月","三月","四月","五月","六月","七月","八月","九月","十月","十壹月","十二月"};
char* week[]={"星期日","星期壹","星期二","星期三","星期四","星期五","星期六"};
int runnian(int year) /*看看這是不是閏年*/
{
if((year%4==0&&year%100!=0)||(year%400==0)) //判斷是否是閏年的
return 1; //
else
return 0;//
}
int month_day(int year,int month) //這個函數用來判斷這年的月分有多少天的
{
int mon_day[]={31,28,31,30,31,30,31,31,30,31,30,31};
if(runnian(year)&&month==2) /*判斷是判斷是否是閏年，是閏年而且這個月是2月那這個月有29天*/
return 29;
else
return(mon_day[month-1]);
}
int DS(int year,int month,int day) /*計算輸入的日期對應的星期,DS=DaySearch*/
{
int c=0;
float s;
int m;
for(m=1;m<month;m++)
c=c+month_day(year,m); //計算輸入的月分的累計天數
c=c+day; //計算日期在這壹年中是第幾天
s=year-1+(int)(year-1)/4+(int )(year-1)/100+(int)(year-1)/400-40+c;
return ((int)s%7);
}
int PAY(int year)/*這個函數是用來輸出全年的日歷,PAM=print all year*/
{
int temp;
int i,j;
for(i=1;i<=12;i++)
{
printf("\t\t\t%s的日歷\n",month_str[i-1],i); //輸出月分名稱
printf(" Sun\t Mon\t Tus\t Thr\t Wed\t Fri\t Sat\t\n\n");
temp=DS(year,i,1);
for(j=1;j<=month_day(year,i)+temp;j++)
{
if(j-temp<=0)
printf(" \t");
else if(j-temp<10)
printf("%2d\t",j-temp);
else
printf("%2d\t",j-temp);
if(j%7==0)
printf("\n");
}
printf("\n");
}
return 0;
}
int PM(int year,int month)//PM=print month//
{
int temp;
int i,j;
i=month;
printf("\n****************************************************\n");
printf("\t\t %d 年 %2d 月",year,month); //打印年月
printf("\n****************************************************\n");
printf(" 星期日 星期壹 星期二 星期三 星期四 星期五 星期六\n");
temp=DS(year,i,1);
for(j=1;j<=month_day(year,i)+temp;j++)
{
if(j-temp<=0)
printf(" \t");
else if(j-temp<10)
printf("%2d\t",j-temp);
else
printf("%2d\t",j-temp);
if(j%7==0)
printf("\n");
}
printf("\n");
return 0;
}
#define NY 2017
#define NM 6
#define ND 4 //把今天的日期定義為壹個常量
int DJT(int year,int month,int day) //計算某年某天是這年的第幾天
{
int i;
for(i=1;i<month;i++)
{
if(i==1||i==3||i==5||i==7||i==8||i==10||i==12)
day+=31;
else if(i==2)
{
if(runnian(year)==1)
day+=29;
else
day+=28;
}
else
day+=30;
}
return(day);
}
void JL(int year,int month,int day) //分情況計算輸入的年月日與今天的天數
{
int x,y,z,i;
z=DJT(NY,NM,ND);
y=DJT(year,month,day);
if(year<NY)
{
for(i=year;i<NY;i++)//不同年用循環判斷中間年份的天數並加上
{
if(runnian(year)==1)
z+=366;
else
z+=365;
}
x=z-y;
}
else if(year>NY)
{
for(i=NY;i<year;i++)
{
if(runnian(year)==1)
y+=366;
else
y+=365;
}
x=y-z;
}
else
{
if(month<NM)//同年不同月將兩個日期在今年的天數相減
{
x=z-y;
}
else if(month>NM)
{
x=y-z;
}
else
{
if(day<ND)//同年同月直接將天數相減
x=ND-day;
else if(day>ND)
x=day-ND;
else
x=0;
}
}
printf("%d年%d月%d日距離今天還有%d天。\n",year,month,day,x);
}
void WEEK(int year,int month,int day) //判斷輸入日期是第幾周
{
int k;
k=DS(year,month,day);
switch(k)
{
case 0:printf("%d年%d月%d日是星期日。\n",year,month,day);break;
case 1:printf("%d年%d月%d日是星期壹。\n",year,month,day);break;
case 2:printf("%d年%d月%d日是星期二。\n",year,month,day);break;
case 3:printf("%d年%d月%d日是星期三。\n",year,month,day);break;
case 4:printf("%d年%d月%d日是星期四。\n",year,month,day);break;
case 5:printf("%d年%d月%d日是星期五。\n",year,month,day);break;
case 6:printf("%d年%d月%d日是星期六。\n",year,month,day);break;
}
}
int main()
{
int option,da;
char ch;
int year,month,day;
while(1)
{
printf("----------------- 請選擇功能: -------------------\n");
printf(" 1.顯示某年日歷 \n");
printf("-------------------------------------------------------------------------\n");
printf(" 2.顯示某年某月月歷 \n");
printf("-------------------------------------------------------------------------\n");
printf(" 3.計算距離今日天數，顯示今日為周幾 \n");
printf("-------------------------------------------------------------------------\n");
printf(" 4.退出 \n");
printf("請輸入您的選擇: ");
scanf("%d",&option);
switch(option) //用來選擇執行
{
case 1:
while(1)
{
printf("\n請輸入1930~2030任意年份:");
scanf("%d",&year);
PAY(year);
printf("\nContinue(Y/N)?");
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}break;
case 2:
while(1)
{
printf("\n請輸入年份和月份(XXXX,XX):");
scanf("%d,%d",&year,&month);
PM(year,month);
printf("\nContinue(Y/N)?");
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}break;
case 3:
while(1)
{
printf("\請輸入年,月,日(XXXX,XX,XX):");
scanf("%d,%d,%d",&year,&month,&day);
JL(year,month,day);
WEEK(year,month,day);
printf("\nContinue(Y/N)?");
fflush(stdin);
scanf("%c",&ch);
if(ch=='N'||ch=='n')
break;
}break;
case 4:
fflush(stdin);
printf("Exit?(Y/N)");
scanf("%c",&ch);
if(ch=='Y'||ch=='y')
exit(1);
break;
default:
printf("\n輸入錯誤，請輸入1到4之間的阿拉伯數字:\n");break;
}
}
return 0;
}